Shell Programming and Scripting

I have an application consisting of a number of perl files. I want to find those perl files that have no documentation yet, so I tried the following from the root level of the directory where the application resides:

Code:

perldoc -r *

The output is something like the following:

Code:

No documentation found for "Build.PL".
No documentation found for "CHANGES".
...etc...

then the output stops at a file which apparently does have perl documentation:

Code:

Perldoc is only really meant for reading one document at a time.

How do I make the script continue? Then afterwards, I can do the following for those files that dont have documentation:

Code:

grep "No documentation found for"

How about a for loop ? Something like

Code:

$ for f in *; do perldoc $f; done

OR

Code:

$ find . -type f | xargs perldoc

Thanks for your response. The basic error still occurs though, which is:

Code:

Perldoc is only really meant for reading one document at a time.
So these parameters are being ignored:[list of files that have been ignored]

Of course I would have to do some filtering to only pick out the .pl and .pm files. The essence is that the loop should not abort, but how to do that?