Shell Programming and Scripting

Hello all

I have a string like

" Have Fun for the rest of the day &#33. I will meet you tomorrow!"

&#33 is the HTML Equivalent of ! symbol.
From the above string, i would like to remove only the HTML encoded special characters.
Output should be like

" Have Fun for the rest of the day . I will meet you tomorrow!"

Please reply

$str =~ s/&#[0-9]+//g;

I got it. Thanks for the reply
But i have a Q again
i jsut came to know that to put a HTML number, we can type $#somenumber or &string.

For greater than symbol
we can say &#62 or &gt.

If the string is like

" 20 &gt than 30. Is &#62 is the right symbol to use. Look for > ".
After stripping HTML Encoded, my output should be like

" 20 than 30. Is is the right symbol to use. Look for > ".

Please reply. I appreciate your response

The above are incorrect. You need to add a semi-colon (';') after each of the character entities.

A trivial modification of the previous regex.

$str =~ s/&[^;]+\;//g;