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Delete chars after dot "."

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# 1  
Old 07-26-2010
Delete chars after dot "."
Hi,

I require to delete all characters after a dot "." from a string. For e.g.

Code:
 
input_var="/home/dips/file_1_20100726.txt.gz /home/dips/file_2_20100726.txt.gz /home/dips/file_3_20100726.txt.gz"
 
output_var="/home/dips/file_1_20100726 /home/dips/file_2_20100726 /home/dips/file_3_20100726"

I tried to acheive this, but everytime I either delete only dots "."
but not the chars after "." or I could only delete the last ".gz".

I am not sure how to delete chars after "." dot from each of the string separated by a space. Also I don't want to use a loop instead I am looking for a single command. Can this be done through a single command? Please suggest.

Thanks in advance.

-dips
# 2  
Old 07-26-2010
Code:
echo ${input_var} | sed 's/\..[^.]*\.gz/ /g'



---------- Post updated at 03:11 AM ---------- Previous update was at 03:08 AM ----------

Code:
#!/bin/bash
declare -a s
s=($input_var)
echo ${s[@]%.txt*}
echo ${s[@]//.txt.gz/}

# 3  
Old 07-26-2010
MySQL
try this Smilie
Code:
# echo $input_var | sed 's/\.[a-z.]*//g'
/home/dips/file_1_20100726 /home/dips/file_2_20100726 /home/dips/file_3_20100726

# 4  
Old 07-26-2010
Thanks both of you!!

I figured something myself:
Code:
echo ${input_var} | sed 's/\.[^ ]*/ /g'

which would be independent of the extensions in the file name.

-dips
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