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using the $1 $2 etc for words in awk

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Top Forums Shell Programming and Scripting using the $1 $2 etc for words in awk
# 8  
Old 07-22-2010
Thanks man.
Quote:
Originally Posted by radoulov
This is scottn's code, not mine.
The 1 simply means true, which in the pattern/expression part causes the execution of the default action, which is print the current record.
Thanks man but one query that only print is a default command or any thing else?
# 9  
Old 07-22-2010
Quote:
Originally Posted by scottn
Or, perhaps:
Code:
$ echo 1 2 3 4 5 6 | awk '{if( NF > 2) { $3 = RS $3}}1'
1 2
3 4 5 6

Good stuff, but I actually need this printing stuff in an else if in my script, and I have about 3 else if's, and just substituting the command into it doesn't work! Could you show me how you would do it?

I have something like:

Code:
/usr/bin/nawk '
{if ( NF>2 ){
     if ($3 ~/and/){
         print $0}
    if ($3 ~/do/){
        print $0}}
else if ($3 ~/and/){
        {$4 = RS $4}}1
else if ($3 ~/do/){
        {$4 = RS $4}}1
else if ($3 ~/\./){
        {$3 = RS $3}}1
 
}
 
else{
print $0}
 
}' filename.txt


NOTE: im using Solaris

PLEASE HELP! thanks!
# 10  
Old 07-22-2010
Quote:
Originally Posted by linuxkid
Good stuff, but I actually need this printing stuff in an else if in my script, and I have about 3 else if's, and just substituting the command into it doesn't work! Could you show me how you would do it?

I have something like:

Code:
/usr/bin/nawk '
{if ( NF>2 ){
     if ($3 ~/and/){
         print $0}
    if ($3 ~/do/){
        print $0}}
else if ($3 ~/and/){
        {$4 = RS $4}}1
else if ($3 ~/do/){
        {$4 = RS $4}}1
else if ($3 ~/\./){
        {$3 = RS $3}}1
 
}
 
else{
print $0}
 
}' filename.txt

NOTE: im using Solaris

PLEASE HELP! thanks!
Hi.

Originally I posted:
Code:
$ echo 1 2 3 4 5 6 | awk '{if( NF > 2) { $3 = RS $3; print} }'

but changed it. Maybe that is closer to what you needed?

I have to be honest... I don't fully understand your logic (and overuse of curly brackets!), but this is what I think you were looking for:
Code:
/usr/bin/nawk '{
  if ( NF>2 ) {
    if ( ($3 ~ /and/) || ($3 ~ /do/) )
      $4 = RS $4
    else if ($3 ~ /\./)
      $3 = RS $3
    print
  } else
    print
}' filename.txt

Last edited by Scott; 07-22-2010 at 11:06 AM.. Reason: Slight change to code
# 11  
Old 07-22-2010
Hammer & Screwdriver
Quote:
Originally Posted by scottn
Hi.
I have to be honest... I don't fully understand your logic (and overuse of curly brackets!), but this is what I think you were looking for:
Neither do i! as they say, im "yung and lernin". but thanks anyway, from your solution I managed to work it out all on my own (with a bit of your help though ofcourse!)
# 12  
Old 07-22-2010
Quote:
Originally Posted by linuxkid
Neither do i! as they say, im "yung and lernin". but thanks anyway, from your solution I managed to work it out all on my own (with a bit of your help though ofcourse!)
Smilie

Nice one!
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