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Problem with copying a date value to another variable

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# 8  
Old 07-21-2010
Hi.

You have the closing backtick in the wrong place, and the echo is not required...
Code:
dte=`echo ls -ltr` | tail -1 | awk '{print $6 $7}' | date +%Y%m%d

Should be:
Code:
dte=`ls -ltr | tail -1 | awk '{print $6 $7}' | date +%Y%m%d`

If [B]

In Linux you can also say:

Code:
dte=$(ls -ltr --time-style=+%Y%m%d | tail -1 | awk '{print $6}')

Last edited by Scott; 07-21-2010 at 12:47 PM.. Reason: I was way off the mark first time!
This User Gave Thanks to Scott For This Post:
michaelrozar17
# 9  
Old 07-21-2010
Quote:
dte=`echo ls -ltr` | tail -1 | awk '{print $6 $7}' | date +%Y%m%d
echo ${dte}
bate=${dte}
echo bate value is ${bate}
cycle=20100702
if [[ ${bate} -gt ${cycle} ]]
then
echo VALIDATE
else
echo DO NOT VALIDATE
fi
Assuming this not a Linux with an extended format ls (in which case pludi's Linux solution is good), I think that the O/P is assuming that piping the date from a directory listing to the unix "date" command will convert the format of the piped input. It won't.

If the script is intended to find files modified after a particular date held in $cycle, it may be better to "touch" a temporary file with that date and use "find" with the "-type f -newer filename" options.
# 10  
Old 07-22-2010
Thanks Scottn - it worked out successfully now.
Thanks to Methyl too.
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