Shell Programming and Scripting

Hey folks

My problem is simple. For my first stash of movies, I used a naming convention of YEAR_MOVIE_NAME__QUALITY/ for each movie folder. For example, if I had a 1080p print of Minority Report, it would be 2002_Minority_Report__1080p/.

The 2nd time around, I changed the naming convention to one that would be easier to read for humans and machines. It changed to MOVIE_NAME_YEAR[_U]/. This was done since when I ls the directory, this will give me movies by movie name, making it easier to scroll through. Also, quality was irrelevant for me know (in the directory name itself) so it went away. The third change was the addition of `_U'. This is a flag at the end of each movie directory name if the movie has not yet been watched. Thus, if I wanted to see list all movies in my stash that I haven't yet seen, then I would do `ls *_U'. So Minority Report would be Minority_Report_2002/. If I hadn't yet seen it, it would be Minority_Report_2002_U.

Now, I have these two different stashes of movies named under different conventions. I want to put them all together and name them according to convention 2 (i.e. MOVIE_NAME_YEAR[_U]).

In other words, I want to change the names of a set of directories from YEAR_MOVIE_NAME__QUALITY to MOVIE_NAME_YEAR. I'll manually add the `_U' flags later. I'm sure this is trivial to solve using sed or awk, but I don't have much experience in either.

Any thoughts?

You can use something like this:

Code:

for movie_dir in [12][09][0-9][0-9]_*/; do
  year=${movie_dir%%_*} tmp=${movie_dir%__*}
  movie=${tmp#${year}_}
  [ -d "$movie"_"$year" ] && {
    printf 'directory %s already exists ...\n' "$movie"_"$year"
    continue
    }
  mv -- "$movie_dir" "$movie"_"$year"
done

Code:

#!/bin/bash

ls . | while read OLD_NAME
do
  YEAR=$( echo $OLD_NAME | awk -F '_' '{print $1}' )
  CRAP=$( echo $OLD_NAME | awk -F '_' '{print $NF}' )
  NEW_NAME=$( echo $OLD_NAME | sed -e "s/$CRAP/$YEAR/" -e "s/$YEAR\_//" )
  mv -v $OLD_NAME $NEW_NAME
done

exit 0
#finis

Code:

[house@leonov] ls .
2001_Some_Film_whatever/ 2002_Some_Other_Film_nn/ 
[house@leonov] bash code.bash
2001_Some_Film_whatever -> Some_Film_2001
2002_Some_Other_Film_nn -> Some_Other_Film_2002

You may want to extend the loop with a read statement to add the "u" switch interactively while converting the file names one by one ...

Get the new name directly from old folder name.

Code:

for movie_dir in [12][09][0-9][0-9]_*/; do
  new_name=$(echo $movie_dir |awk 'BEGIN{FS=OFS="_"}{print $2,$3,$1}')
  [ -d $new_name ] && {
    printf 'directory %s already exists ...\n' $new_name
    continue
    }
  mv "$movie_dir" "$new_name"
done

---------- Post updated at 07:12 PM ---------- Previous update was at 07:10 PM ----------

What's the purpose to add "--" after mv, I never use like this way before.

-- indicates end of options. It's there for extra protection.
Consider the extreme case when the movie name begins with a dash:

Code:

% mv 2010_-90_Celsius__1080p -90_Celsius_2010
mv: unknown option -- 9
Try `mv --help' for more information.
% mv -- 2010_-90_Celsius__1080p -90_Celsius_2010
%