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Insert a function on an script's output

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# 1  
Old 07-15-2010
Insert a function on an script's output
Hi, I have this code:

Code:
#Convert epoch2date
getdate()
{
perl -e '
    use POSIX qw(strftime);
    $mydate = strftime "%c", localtime($ARGV[0]); 
    print $mydate; ' $1
}   

lsuser -a time_last_login gecos $username  |awk '{print $1,$2,$3,$4}'|sed -e 's/gecos=/  Nombre: /' -e 's/time
_last_login=/ultimo_login=/'

and its Output:

Code:
acc17 ultimo_login=1202905371   Nombre: User1
acc18 ultimo_login=1203356871   Nombre: user2
orion ultimo_login=1145539155   Nombre: User3
tomcat ultimo_login=1164038769   Nombre: User4
acc19 ultimo_login=1203334238   Nombre: User5

I want to convert

Code:
acc17 ultimo_login=Thu Jul 15 15:16:11 CEST 2010   Nombre: User1
acc18 ultimo_login=Mon Feb 18 18:47:51 CET 2008  Nombre: user2
orion ultimo_login=Thu Apr 20 15:19:15 CEST 2006 Nombre: User3
tomcat ultimo_login=Mon Nov 20 17:06:09 CET 2006 Nombre: User4
acc19 ultimo_login=Mon Feb 18 12:30:38 CET 2008 Nombre: User5

How can I use this function from the command output above?

thanks
ISrael.

Moderator's Comments:
Mod Comment Use [CODE] tags, not [QUOTE] tags
Last edited by Scott; 07-16-2010 at 06:58 AM..
# 2  
Old 07-15-2010
Code:
lsuser -a time_last_login gecos $username |
awk '{print $1,$2,$3,$4}' |
sed -e 's/gecos=/ Nombre: /' -e 's/time_last_login=/ultimo_login=/' |
while read ACCOUNT LOGIN NUM USER; do echo $ACCOUNT ${LOGIN%%[0-9]*} $(getdate ${LOGIN##*=}) $NUM $USER; done

I've assumed that you have created the "getdate" function in the Bash shell. The function invocation can be run as a shell command in that case.

tyler_durden
# 3  
Old 07-16-2010
Worked!! Very nice tyler.. thanks a lot!

regards
israel
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