Shell Programming and Scripting

OK here is my problem. Ive been trying to write a script where i use the order "find".

For example if i wont to find some file in the sql_work directory using the script. You use the command: loc sql_work "q*" in order to find all the queries in the directory.
Is there any other way to do it, like for example: loc sql_work q* without using the " " which secure the argument from the shell?

Here is the script:

#! /bin/csh
if($#argv == 0) then
echo Usage is $0 path filename
echo or $0 filename
exit 1
endif
if($#argv == 1) then
foreach arg($argv)
set tmp = `find ~ -name "$arg"` >& /dev/null
if("$tmp" != "") then
echo $tmp
else
echo No files matching name "$argv[1]"
exit 1
endif
end
exit 0
endif
if($#argv == 2) then
if(! -e "$argv[1]") then
echo "$argv[1]" not valid directory
exit 2
endif
set tmp = `find ~/"$argv[1]" -name "$argv[2]"` >& /dev/null
if("$tmp" != "") then
echo $tmp
else
echo No files matching name "$argv[2]"
exit 1
endif
exit 0

endif



Thank you in advance!!!