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Looking for awk code explaination

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# 1  
Old 07-14-2010
Looking for awk code explaination
Code:
{ # print NF,NR,$0;
if ( ($(NF-1) != 0) && ($NF != 0) )
  {if ($(NF-1) > $NF)
    {percent=$(NF-1)/$NF-1;}
  else
    {percent=$NF/$(NF-1)-1;}
  }
printf "%8.4f\%\n",percent*100;
if (percent > 0.05||percent < -0.05 ){exit 1;}
}'

Moderator's Comments:
Mod Comment Use code tags please, ty. Also try to use a more descriptive subject next time.
Last edited by zaxxon; 07-14-2010 at 04:34 AM.. Reason: code tags and changed subject
# 2  
Old 07-14-2010
If the no. of fields on the input file is 1, then it will print 0.0000%, else it will always print 100.0000%.

Thanks,
Sameer.
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