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Need advise to process the file with awk

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Top Forums Shell Programming and Scripting Need advise to process the file with awk
# 1  
Old 07-12-2010
Need advise to process the file with awk
Hi gurus,

i need your advise on how to process this file using awk.
i have this file
Code:
                        COLA  COLB  COLC  COLD  COLE  COLF  COLG  COLH
 AAAA                   86    111   122   133   144   155   266   377
 BBBB                   70    211   222   233   244   255   266   377

but i want to take some of the columns only, but keep the formatting, so the desired output is like

Code:
                        COLA  COLB  COLC  COLD  COLG  COLH
 AAAA                   86    111   122   133   266   377
 BBBB                   70    211   222   233   266   377

i tried using awk, but i cannot get the formatting right,
and COLA is considered as column 1 instead of column 2

Many thanks in advance for your help.
# 2  
Old 07-12-2010
Maybe ...:

Code:
#!/bin/bash

LC=0
while read C1 C2 C3 C4 C5 C6 C7 C8 C9
do
  LC=$(($LC+1))
  if [ $LC -eq 1 ]
  then
    printf '\t %s \t %s \t %s \t %s \t %s \t %s \n' $C1 $C2 $C3 $C4 $C7 $C8
  else
    printf '%s \t %s \t %s \t %s \t %s \t %s \t %s \n' $C1 $C2 $C3 $C4 $C5 $C8 $C9
  fi
done < in.file

exit 0
#finis

Code:
[house@leonov] bash code.bash
         COLA    COLB    COLC    COLD    COLG    COLH
AAAA     86      111     122     133     266     377
BBBB     70      211     222     233     266     377

# 3  
Old 07-12-2010
hi dr.house

thanks, the formatting looks great, but when i tried this is my output

Code:
#!/bin/bash

LC=1
while read C1 C2 C3 C4 C5 C6 C7 C8 C9
do
  if [ $LC -eq 1 ]
  then
    printf '\t %s \t %s \t %s \t %s \t %s \t %s' $C1 $C2 $C3 $C4 $C7 $C8
  else
    printf '%s \t %s \t %s \t %s \t %s \t %s \t %s' $C1 $C2 $C3 $C4 $C5 $C8 $C9
  fi
  printf '\n'  LC=$(($LC+1))
done < in.file

#finis

Code:
[root@localhost ~]# ./bash 
         COLA    COLB    COLC    COLD    COLG    COLH
         AAAA    86      111     122     155     266
         BBBB    70      211     222     255     266

looks like line 2 and line 3 is read as LC=1
# 4  
Old 07-12-2010
I updated my code while you were testing it (sorry ...). Therefore, please re-run your test with the (hopefully) debugged version currently published in my recent post.
# 5  
Old 07-12-2010
hi dr. house

thanks for your help, it works perfectly,
will try to play around with it.
# 6  
Old 07-12-2010
Code:
$ cat infile
                       COLA  COLB  COLC  COLD  COLE  COLF  COLG  COLH
 AAAA                   86    111   122   133   144   155   266   377
 BBBB                   70    211   222   233   244   255   266   377

$ head -1 infile|awk '{printf "%15s %s %s %s %s %s\n", $1, $2, $3, $4, $7, $8}' > outfile

$ awk 'NR > 1 {printf "%-10s %-4s %-4s %-4s %-4s %-4s %-4s\n", $1, $2, $3, $4, $5, $8, $9}' infile >> outfile

$ cat outfile
           COLA COLB COLC COLD COLG COLH
AAAA       86   111  122  133  266  377 
BBBB       70   211  222  233  266  377

# 7  
Old 07-12-2010
Hi Soleil
Thanks for another great solution.
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