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need with script which i am doing to print the status

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# 1  
Old 07-07-2010
need with script which i am doing to print the status
Code:
df -h | awk '{if ($5 < 86%) {"   " print 'status ok'}  else {print 'Highdisk usage'}}

i am trying to check if th disk usage is above 86% please let me know what the problem.
Last edited by Scott; 07-28-2010 at 04:41 AM.. Reason: Code tags
# 2  
Old 07-07-2010
you should get rid of % symbol, to perform maths comparision.
# 3  
Old 07-07-2010
if i get rid of the % symbol shd i put it as a field seperator.in the awk
# 4  
Old 07-07-2010
Code:
df -h | awk 'sub("%","",$5) { if ( $5 > 86 ) { print $NF,"is over 86%" } else { print $NF,"is OK" } }'

# 5  
Old 07-07-2010
its give me this error while running it

Code:
"a1.sh" 4 lines, 103 characters
hostname> ./a1.sh
+ + awkdf  {if ($5 < 86) {"   " print status -hok}  else {print Highdisk
 usage}}

awk: syntax error  Context is:
>>>     {if ($5 < 86) {"   " print      <<<

Last edited by Scott; 07-28-2010 at 04:41 AM.. Reason: Code tags
# 6  
Old 07-07-2010
Hi,
Try this out -----

Write a script

Code:
#!/bin/sh
output=`df -h | awk '{ print $5}'`
per=$(echo $output |  cut -d'%' -f1 )
if [ $per -ge 86 ]; then
echo "HighDisk Usage"
else
echo "Status OK"
fi

Last edited by Scott; 07-28-2010 at 04:41 AM.. Reason: Code tags
# 7  
Old 07-07-2010
thanks
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