Shell Programming and Scripting

Hi,

I have a scenario in which I have to substitute the variable to call the procedure "login" in Tcl.

Code:

for {set i 1} {$i<=2} {incr i} {
login "$spawn_id$i"
}

I have the variables $spawn_id1 and $spawn_id2 in the beginning of the script which I'm trying to pass to the procedure "login". So I tried to use an for loop to substitute the numeral value of spawn_id.But then in this case both the $spawn_id and the $i are replaced with the new values, however I need the $i to be substituted first which makes the variable $spawn_id1 and then the value of variable $spawn_id1 should be passed to the calling procedure.

---------- Post updated at 05:10 PM ---------- Previous update was at 02:44 PM ----------

Could anybody help in this case please.

try if this works for you

Code:

for set ${i} 1} {${i} <=2} {incr ${i}} {
login "$spawn_id"${i}
}

Hi dazdseg,

Thanks for your effort but the syntax didn't help. I saw the below code from another post named "Variable Substituion" by cfajohnson:

Code:

  BITTER=qwerty
  SUBSET_BIT_NUM=TER
  IFS=E
  eval echo '$BIT'$SUBSET_BIT_NUM  ## unreliable
  eval echo "\$BIT$SUBSET_BIT_NUM" ## correct