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Number of days in the previous month

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# 8  
Old 08-09-2010
Code:
cal |  awk 'NF{p=$(NF)}END{print p}'

# 9  
Old 08-09-2010
Code:
set - $(cal $(( ($(date +%-m) + 11-1) %12+1)) $(date +%Y))
eval echo \${$#}

Last edited by daPeach; 08-10-2010 at 05:18 AM..
# 10  
Old 08-10-2010
Quote:
Originally Posted by lyoncc
- HPUX POSIX Shell -


This month, the command below is returning an error...

# X=$(cal $(( ( $(date +%m) + 11 - 1 ) %12 + 1 )) $(date +%Y) | grep -v '[A-Za-z]' | wc -w)

sh: 08 + 11 - 1 ) %12 + 1 : The specified number is not valid for this command.

It seemed to work last month....any ideas?

TIA!!!

Some programs interpret a number with a leading zero as octal. So it worked for the previous months, because octal 1..7 represent the same value as decimal 1..7 . But 08 does not exist in octal.

In short: you need to get rid of the leading 0 that the date command produces, then I think t will work as intended.

S.
# 11  
Old 08-10-2010
Quote:
X=$(cal $(( ( $(date +%m) + 11 - 1 ) %12 + 1 )) $(date +%Y) | grep -v '[A-Za-z]' | wc -w)
This does not give a syntax error in HP-UX Posix Shell.
It gives the answer 31 which is correct for the days in July 2010.

It is interesting how it works in a January because it correctly assumes that the days in December are the same this year and last year.
# 12  
Old 08-10-2010
Quote:
Originally Posted by lyoncc
that works on my gentoo system, but it doesn't return anything on the hp

Code:
 X="`cal -3 | sed -n '/29/p' | sed 's/  *$//;s/.*\([0-9][0-9]\)     .*/\1/'`"
# echo $X
 
#

hmm i cant test on hp-ux because i dont have it Smilie
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