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plz, i wait your help, AWK problem

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Top Forums Shell Programming and Scripting plz, i wait your help, AWK problem
# 8  
Old 06-27-2010
So the array is unecessary:

Code:
awk '$3 == 1 && $5 == "tcp" {
  $1 == "+" && node_plus += $6
  $1 == "-" && node_minus += $6
  print $2, node_plus, node_minus, \
    node_plus - node_minus
    }' OFS='\t' infile

# 9  
Old 06-27-2010
is this correct if i want only for node 1

Code:
($5 == "tcp" && $3=="1") {
  $1 == "+" && node_plus[$3] += $6
  $1 == "-" && node_minus[$3] += $6
  print $2, node_plus[$3], node_minus[$3], \
    node_plus[$3] - node_minus[$3]
    }

Last edited by radoulov; 06-27-2010 at 07:11 PM.. Reason: Added code tags!
# 10  
Old 06-27-2010
Yes, but the arrays are redundant, see my previous post.
# 11  
Old 06-27-2010
i try your awk program and l reply the result
please how exactly write the program, like this script or other:

Code:
BEGIN{}

awk'$3 == 1 && $5 == "tcp" {
  $1 == "+" && node_plus += $6
  $1 == "-" && node_minus += $6
  print $2, node_plus, node_minus, \
    node_plus - node_minus
    }' OFS='\t' infile
END{""}

Last edited by Scott; 06-27-2010 at 07:40 PM.. Reason: Code tags
# 12  
Old 06-27-2010
i try your awk program and l reply the result
please how exactly write the program, like this script or other:

Code:
BEGIN{}

awk'$3 == 1 && $5 == "tcp" {
  $1 == "+" && node_plus += $6
  $1 == "-" && node_minus += $6
  print $2, node_plus, node_minus, \
    node_plus - node_minus
    }' OFS='\t' infile
END{""}


---------- Post updated at 05:28 PM ---------- Previous update was at 05:19 PM ----------

plz
i have the following result :
Code:
[asaadaoui@elec ~]$ awk -f try.awk salem.tr> try.txt
awk: try.awk:4: awk '$3 == 1 && $5 == "tcp"{
awk: try.awk:4:     ^ invalid char ''' in expression

plz, how exactly i write the program

Moderator's Comments:
Mod Comment Please use code tags


---------- Post updated at 06:11 PM ---------- Previous update was at 05:28 PM ----------

Hi Radoulov,
Congratulation
The program is correct

i wrote the following program :

Code:
BEGIN { node_plus=0;node_minus=0; }
{

$3 == 1 && $5 == "tcp"
{
  $1 == "+" && node_plus += $6
  $1 == "-" && node_minus += $6
  print $2, node_plus, node_minus, \
    node_plus - node_minus
}
} 
END {""}

and I have the following part of result ( tracefile ):
Code:
0.02 40 0 40
0.02 40 40 0
0.02 80 40 40
0.02 80 80 0
0.025032 80 80 0
0.025032 120 80 40
0.025032 120 120 0
0.025032 120 120 0
0.025032 160 120 40
0.025032 160 160 0
0.030064 160 160 0
0.030064 200 160 40
0.030064 200 200 0
0.030064 200 200 0
0.030064 240 200 40
0.030064 240 240 0
0.035096 240 240 0
................
.................
................

thank you very much, Sir RADOULOV.
Last edited by radoulov; 06-28-2010 at 09:22 AM.. Reason: Code tags
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