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How to traverse directory structure and sum size of files?

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# 1  
Old 06-29-2010
This may help in getting the file size of all the files
Code:
sum=0
for k in `find . -mtime -730 -mtime +365 -exec ls -l {} \+ | awk '{print $5}'`
do
   sum=$((sum+k))
done
echo "Total file size is $sum"

Last edited by radoulov; 06-29-2010 at 04:37 AM.. Reason: Please use code tags!
# 2  
Old 06-29-2010
Quote:
Originally Posted by sanjaypraj
Code:
sum=0
for k in `find . -mtime -730 -mtime +365 -exec ls -l {} \+ | awk '{print $5}'`
do
   sum=$((sum+k))
done
echo "Total file size is $sum"

Another untested version of the above.

Code:
find . -mtime -730 -mtime +365 -exec ls -l {} \+  | awk '{  x += $5  } END {print "Total file size is "x}'

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