10 More Discussions You Might Find Interesting
1. HP-UX
current date command runs well
awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
subtract 30 days fails
awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
2. Red Hat
Hi all,
as i have multiple broken pipes on ssh sessions,
i need to find out after how much time it happens,
ssh root@testServer
root@testServer's password:
ssh:notty
Last login: Thu Apr 6 06:41:16 2017 from 10.10.10.2
#
but when broke pipe happen i don't have any idea after how much... (3 Replies)
Discussion started by: charli1
3 Replies
3. UNIX for Dummies Questions & Answers
Dear all,
I have an user passing 2 parameter 31/03/2015 and 02/04/2015 to a ksh script. How to print the start date to end date.
Expected output is :
31/03/2015
01/04/2015
02/04/2015
Note :
1. Im using aix and ksh
2. I have tried to convert the given input into a date, didnt... (0 Replies)
Discussion started by: mr.rajaravi
0 Replies
4. Shell Programming and Scripting
Hi all,
Need an urgent help on the below scenario.
script:
awk -F","
'BEGIN { #some variable assignment}
{ #some calculation and put values in array}
END {
year=#getting it from array and assume this will be 2014
month=#getting it from array and this will be 05
date=#... (7 Replies)
Discussion started by: vijaidhas
7 Replies
5. Shell Programming and Scripting
hi all
I would like to help me find the problem with this script to find and print to the screen a specific date of a log file that I have on my server, the date it is received as the first argument in the script $ 1
Here I show you a few lines that made the idea of my log file:
****... (4 Replies)
Discussion started by: gilmore666
4 Replies
6. Shell Programming and Scripting
Hello everyone, I have this script here:
use Time::Local;
opendir (D, $ARGV) or die "Cant open";
foreach $file (readdir D)
{
$path = "$ARGV/$file";
next if ! -T $path;
$last_mod = (stat $path);
($sec,$min,$hour,$mday,$mon,$year,$wday) = localtime ($last_mod);
printf "%-15s:... (4 Replies)
Discussion started by: new bie
4 Replies
7. UNIX and Linux Applications
Hi to all! I 'm new in unix programing so... may be I decided a wrong tool to solve the problem but anyway... all road goes to rome jajaja.
My question is: There is any way to print date at the END clause of an AWK script. I mean, I'm writing a tool with AWK and the results are redirected to a... (4 Replies)
Discussion started by: fmeriles
4 Replies
8. UNIX for Dummies Questions & Answers
List,
I want to print the first line of my text file (say "me you"), preceded by the current date/time.
Something like (pseudo code):
awk '{print date,$1}'
I don't have a lot of awk knowledge (understatement), so forgive me if the answer is obvious... (3 Replies)
Discussion started by: philipz
3 Replies
9. Shell Programming and Scripting
Hi friends
sftpCmd.txt
-----------------
!echo "Getting files from sftp"
!echo "----------------"
cd /home/msgGoogle/PLATFORM/PROD/MIMUS/outbound/ARCHIVE/invsnap
!echo "folder created"
!date
mget ???050108*.txt output
!echo "------------------"
!echo "Completed : "
!echo... (3 Replies)
Discussion started by: kittusri9
3 Replies
10. Shell Programming and Scripting
The line is simple, use " '{ print $1"]"$2"\"$3THE " NEEDS TO GO HERE$4 }'
I've tried \", "\, ^" and '"" but none of it works. What am I missing? Putting in the [ between $1 and $2 works fine, I just need to do the same with a ".
Thanks. (2 Replies)
Discussion started by: LordJezo
2 Replies