expr+float argument: how can i do?


 
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# 1  
Old 05-05-2004
expr+float argument: how can i do?

Hi everybody,
I want to know how can i use the command 'expr' to manipulate float number , i have a shell bash and when (for example) i do:
y1=`expr \( 1/ 16 \)`
it returns 0
and if i do
y1=`expr \( 1.6 / 16 \)`
it returns non numeric argument.
is there another command for mathematic operations?
thank you for your help in advance
# 2  
Old 05-05-2004
Use bc
Code:
echo "1.6 * 1.6" | bc

# 3  
Old 05-05-2004
but i need more precision: 0.0.27 * 0.54 (for example)
is it possible?
# 4  
Old 05-05-2004
ah ok , i see now, i have to choose the number bhind the comma

thank you very much for your help
# 5  
Old 05-05-2004
scale=n sets n digits of precision beyond the decimal in bc.

The bc man page has a lot of information.
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