Shell Programming and Scripting

Alright, try these in that case:

Awk:

Code:

awk '/server/{if(p) print p; print; if(getline) print}{p=$0}' infile

Sed:

Code:

sed -n '/server/{x;1!p;g;$!N;p};h' infile

Code:

awk '/server/{if(p) print p; print; if(getline) print}{p=$0}' infile

that line works for me,, thanks a lot...great help..

---------- Post updated at 04:43 AM ---------- Previous update was at 04:43 AM ----------

the sed was not working...thanks..really..

Code:

awk ' /server/ { ME=$0;getline; printf("%s\n%s\n%s\n",NI,ME,$0) } { NI=$0 }'  file.txt

Code:

vmpool -listall| grep -v "===*"

this will work. (-v option displays all the line which doesnt have that specific pattern"

Slight improvement: this also works like grep -C1 for consecutive matches:

Code:

awk '{if(/Asterix/){if(p&&!n)print p; print; n=1} else if(n){print;p=n=0} else{p=$0}}' infile

Hi Scrutinizer,
Your last reply is the most accurate however your prevoius answer on awk is suffice...

vmpool -list_all|awk '/CU/{if(p) print p;print; if(getline) print}{p=$0}'

vmpool -listall| awk '{if(/CU/){if(p&&!n)print p; print; n=1} else if(n){print;p=n=0} else{p=$0}}' ---> in this command i was able to get the whole details...thanks...


care to explain them??? the if??? p&&n getline etc??

thanks a lot