bash problem with if


 
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# 8  
Old 06-20-2010
Quote:
Originally Posted by Scrutinizer
3. I do not know what you mean with "option"
I mean is there some other selection command to combine with "$1" argument in the for loop?
# 9  
Old 06-20-2010
Hi Luke, the / in the example is literal slash character, not an option.
# 10  
Old 06-20-2010
Yeah I expressed myself bad, however I think to understand.

Thanks for the help.
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