Shell Programming and Scripting

Hi perdarabo

Thanks for the information. I dont know that till you mentioned and i went onto study what GNU/Linux history is. I learned an important point on this. May be some of you knew it already.

do You guys all know that GNU is an operating system and Linux is the kernal for most of the Linux based systems. Most of the users call it "Linux systems" instead of "GNU/Linux system". GNU is a free software foundation which developed a free UNIX like operating system (which is GNU operating system). Go here if you want to learn more on this.

http://www.gnu.org/gnu/linux-and-gnu.html

Once again thanks perdarabo ....

I learned (from the forum) that the way to non-recursively find a <directory> files is:

cd <directory>
find . \( ! -name . -prune \) -type f -print

But that way outputs a list that starts with ./ for all files, and I need to get a list of full pathnames.

What about the following syntax, assuming <directory> starts with /?

find <directory> \( ! -path <directory> -prune \) -type f -print

It seems to work for me (HP-UX 11.0), but I like to know if it has some hidden traps.

Thanks.

How about replacing "-print" with "-exec print - <directory>/{} \;" ?

Just a thought....

bakunin

find `pwd` \( ! -name . -prune \) -type f -print

Coulnd't you just use the whereis command?

How would I modify this command to match files with a particular name? For example, in my directory I have files of the form costing.M01, costing.M02, etc, but there are also many other files that don't begin with costing*. I need to limit the search to this directory only, ie don't search subdirectories, but only match costing.M* files older than 7 days.

Thanks, Andie

With gnu find you can:

cd <dir>
find -type f -name "costing.m*" -maxdepth 1