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Need help using % or like option in shell script

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Top Forums Shell Programming and Scripting Need help using % or like option in shell script
# 8  
Old 06-14-2010
Quote:
Originally Posted by alister
A couple of observations regarding this code:

1. The -n operator takes only one operand. If $a contains any IFS whitespace, the unquoted command substitution will result in more than one word and a syntax error. Since we don't know for certain anything about the range of possible values for $a, this unquoted version might be buggy. It also wouldn't hurt to double quote "$a" within the command substitution.

2. You could simplify your approach to use grep's exit status directly:
Code:
if echo "$a" | grep -q '20100614'; then

Regards,
Alister
Alister ,
I tried the above code but its showing another error
Code:
grep: illegal option -- q
Usage: grep -hblcnsviw pattern file . . .
try again
efmsdapp:/export/home/hut$ help grep
ERROR: Key 'grep' not found (he1)

Here is the code I used

Code:
a=21345zef
b=21345
if echo "$a" | grep -q '21345'; then
echo 'eureka'
else
echo 'try again'
fi

# 9  
Old 06-14-2010
Instead of...
Code:
grep -q '21345'

you could use...
Code:
grep '21345' > /dev/null

This User Gave Thanks to alister For This Post:
srini02
# 10  
Old 06-14-2010
Quote:
Originally Posted by alister
Instead of...
Code:
grep -q '21345'

you could use...
Code:
grep '21345' > /dev/null


Thanks Alister,It worked.
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