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How to process list of files as array in the script

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# 1  
Old 06-07-2010
How to process list of files as array in the script
Hi.,

In my script I have written :

Code:
 
file_list=`ls -lrt /tmp/vinay/act/files |grep "$cdate"| awk '{print $9}'`

To store list of files in the directory. Now I want to access it as list. And for this I tried with :

Code:
 
set -A filearray $file_list
 
if [[ `echo ${filearray[*]}` == "" ]]; then
         print "files not received"
else
 for i in `echo ${filearray[*]}`; do
        print "files received. .. and extra procesing"
done
fi

But on exection it is resulting in following error:

Code:
./cntFiles.sh: -A: bad option(s)

So can you guide me in assingning to array with set -A option OR with any other alternative.


Thank you.
# 2  
Old 06-07-2010
Hi.

set -A is a KSH option.

You can try:
Code:
filearray=($file_list)

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