Shell Programming and Scripting

Hi.,

How to extract the extension of a file which are present in the directory?. In my script I tried something like:

Code:

echo abc_ss_222_54.txt | awk -F"[_.]" '{print $5}'

But I din't got .txt echoed in console. Pl. suggest a solution for this.


And also, for finding a specific pattern of file, I did:

Code:

find `ls -lrt /tmp/vinay/act/files |grep "Jun  7"| awk '{print $9}'` "fdr_c_us_cons_*.[txt|done]"

Here I want to findout fdr_c_us_cons_*.[txt|done] type of file is present in the directory /tmp/vinay/act/files or not.

But it is displaying the o/p as :

Code:

 
find: cannot open fdr_c_us_cons_20100607_121212.txt: No such file or directory
.
.
.

How to resolve the above code to check the existense of the file?


Thank you.

Code:

echo "abc_ss_222_54.txt" | awk -F '.' '{print $NF}'

Code:

ls -1 /tmp/vinay/act/files | grep -E 'fdr_c_us_cons_*.[txt|done]'