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Execution problem with grep script (2 variables)

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# 1  
Old 06-02-2010
Execution problem with grep script (2 variables)
Code:
#!\bin\sh
TEST=test.log
GREP=\usr\bin\grep

$GREP -i 'dog\|cat' ${TEST}

Why doesn't grep run at all?
# 2  
Old 06-02-2010
Try:

Code:
eval $GREP ...

For indirect references you have to use eval.

HTH Chris
This User Gave Thanks to Christoph Spohr For This Post:
jazzaddict
# 3  
Old 06-02-2010
In line 1 and 3 all backslashes should lean the other way...
This User Gave Thanks to Scrutinizer For This Post:
jazzaddict
# 4  
Old 06-02-2010
What about:

Code:
#!/bin/sh
TEST=test.log
GREP=/usr/bin/egrep

$GREP -i 'dog|cat' ${TEST}

This User Gave Thanks to Scott For This Post:
jazzaddict
# 5  
Old 06-02-2010
maybe should you
Code:
eval "$GREP -i 'dog|cat' ${TEST}"

if /usr/bin is your $PATH then you could
Code:
GREP=egrep

too !!
# 6  
Old 06-02-2010
Hi guys! Thanks for your help! I've made the following changes..funny thing is that grep still doesn't run

Code:
#!/bin/sh
TEST=test.log
GREP=/usr/bin/grep

eval "$GREP -i 'dog\|cat' ${TEST}"

And why must I use egrep when grep should work in this case.
# 7  
Old 06-02-2010
Quote:
Originally Posted by jazzaddict
that grep still doesn't run
What does that mean in concrete terms? Is there no output?

Did you try to run that command in the shell and see if it will work?
Code:
/usr/bin/grep -i 'dog\|cat' test.log

Also try
Code:
/usr/bin/grep -iE 'dog\|cat' test.log

This User Gave Thanks to pseudocoder For This Post:
jazzaddict
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