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sed OR-Operation

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# 1  
Old 06-02-2010
sed OR-Operation
Hello,

I'm trying to get the configuration-IP-Addresses from Cisco-configurations

on the Routers they are defined as a Loopback0-interface like this:
Code:
interface Loopback0
ip address 172.23.19.249 255.255.255.255

On the Switches they are defined as a VLAN 80 interface like this
Code:
interface Vlan80
 ip address 172.23.19.177 255.255.255.240

I can get out the IP-Address of the routers using this:
Code:
for i in `ls newestconfigs/ | grep confg`
do 
  echo `cat newestconfigs/$i \
      | awk '/^hostname/ {print $2}'`\
        ": " \
        `cat newestconfigs/$i \
          | sed -n '/^interface.Loopback0/ ,+1p' \
          | grep -o '[0-9]\{1,3\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}' \
          | head -1`
done

Is there a possibility to add the an OR-Operation to the sed-command to scan for "interface Loopback0" OR for "interface Vlan80" and print out the one that first occurs?

Thanks for your help.

Love, Sally

P.S. I'm trying to get familiar with regular expressions since 10 years, this time it seems to work... Smilie
# 2  
Old 06-02-2010
Hi,

try

Code:
sed -n "/interface Loopback0\|Vlan80/p;q" data

to search for either "interface Loopback0" oder "interface Vlan80" and quit after the first hit.

HTH Chris
# 3  
Old 06-02-2010
Hello Chris,

this works, when I do not add the "q". Normally this should be ok, but I have to try how it responds on a device that have both, Loopback0 and Vlan80, eg. Layer-3-Switches.

Thanks, Sally
# 4  
Old 06-02-2010
Another way:
Code:
for i in `ls newestconfigs/ | grep confg`
do
  awk '
      /^hostname/ { host=$2 ; next }
      /^interface (Loopback0|Vlan80)/ { getIp=1 ; next }
      getIp { print host ": " $2 ; exit }

  ' newestconfigs/$i
done

Jean-Pierre.
Last edited by aigles; 06-02-2010 at 08:20 AM..
This User Gave Thanks to aigles For This Post:
Sally[-_-]
# 5  
Old 06-02-2010
this is a really nice solution... Smilie
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