Shell Programming and Scripting

Hi,

I need to pass a run time input to unix script which tracks the list of files in the directory under certain pattern. The files which are matched to the given pattern then need to be stored in the array. Requesint you all to please suggest me the solution.

I gave the below command in the sh file and when i tried to execute i got only the last entry in the filelist. pls suggest me the possible solution.

purpose of storing these file name in the array:
i have a file with list of strings to be searched in above retrived files.

Code:

ls scr* >> filelist

Code:

ls
dead.letter      err_1705101841.txt
error1.file        err_1705101842.txt
practice_a       err_1805101940.log
pyramid.sh       err_1805101942.log
pyramid1.sh     pyramid2.sh           

ls err* >> ls_store.sh

cat ls_store.sh

It works fine..

Hi,
Please try to check by passing input paramter at run time.
Thanks

Assuming filenames don't contain any spaces:

Code:

ARRAY=($(ls err* | tr '\n' ' '))

Hi,

Pasted the code for your reference.

Code:

$ cat run.sh
echo $1
ARRAY=($(ls $1 | tr '\n' ' '))

When i tried to execute,

Code:

$ . ./run.sh scr*

I got the below response only.

Code:

script1.sh

When i tried to execute the cmd directly, i got below update.

Code:

$ ls scr*
script1.sh  script2.sh  script3.sh

Please correct and update, why script1.sh file was alone printed when we pass runtime parameter as scr*

Thanks in advance

Code:

#!/usr/bin/ksh

ls

will nt this works.?
u get all ur file displayed

when u do ls scr* (if their is a file in ur directory that will get displayed)

Hi ..
I need to store the files which are matched to my input pattern. I don'tt want to store all files.