Shell Programming and Scripting

Hello guys,

I am a newbie to Shell Scripting. I have an issue. My requirement is to search a pattern in a file and then replace it with another pattern. Please note that I have thousands of files having the same pattern and I have to replace it running a script.
I have created a script as shown below.But it seems to be not working.

======================

Code:

#!/bin/bash
for i in $(grep -irl "include 'http://www.xx.net" /home/xx/)
do
  sed -i "s/include\ 'http:\/\/www.xx.net/include\ '\/home\/xx\/public_html/g" $i
done
echo "done"

======================

The pattern to be replaced is: include 'http://www.xx.net
New pattern is: include '/home/xx/public_html

Please verify this script and let me know, where I am going wrong.

Regards,

Mahesh Raghunandanan

Try

Code:

 
for i in `grep -irl "include 'http://www.xx.net" /home/xx/`

Try:
Assuming that you are in the directory where all the files are pesent which contains the pattern

Code:

perl -i -ne "s!include 'http://www.xx.net!include '/home/xx/public_html!g;print;" *

Hello amitranjansahu/dennis.jacob ,

Thanks for your response. I tried the way given by amitranjansahu, but still its not working.
As we are supposed to use only unix commands, so I can't use perl also.

Please help me..

sed using s, you can set some other delimiter as /, ex. + => easier to write path rule.

Code:

for i in $(grep -irl "include 'http://www.xx.net" /home/xx/)
do
  sed -i "s+include 'http://www.xx.net+include '/home/xx/public_html+g"  $i
done

If your sed not support -i then use tmp file

Code:

cp  $i $$.tmp
cat $$.tmp | sed  "s...."  > $i