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Find in Bash with -a option

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# 1  
Old 05-13-2010
Data Find in Bash with -a option
Hi,

The proble is below:
Assume i have files starting from "process" then date/time then ".log".
ex .
Code:
process.20100504092942.log
process.20100503152213.log
process.20100430144217.log
process.20100429153644.log
process.20100428121200.log
process.20100427130746.log
process.20100427130350.log
process.20100427070336.log
process.20100427065534.log
process.20100427063908.log
process.20100426122504.log

I run below find statement at command prompt -
Code:
find . \( -name "process*" -a -name "*20100427*" \) -exec ls {} \;

and get the result -
Code:
process.20100427130746.log
process.20100427130350.log
process.20100427070336.log
process.20100427065534.log
process.20100427063908.log

But once I run the same command in on shell .sh file -

got the error -
Code:
find: paths must precede expression
Usage: find [path...] [expression]

It seems it is not able to interpret the \( properly. I gave \\\( i.e \\ + \( to become \( but not resolved.
Could anyone help on this.
Thanks,
Vipin.
Last edited by Franklin52; 05-13-2010 at 02:02 PM.. Reason: Please use code tags, thank you
meetvipin
# 2  
Old 05-13-2010
Have you tried using the bash shell for your script? Put this on the first line of your script:

Code:
/bin/bash

Please post the output.
# 3  
Old 05-14-2010
I mentioned that i am using BASH.
I found th problem, I was not giving the double quotes for the string -

find . \( -name "${PROCESS_NAME}*" -a -name "*${File_Date}*" \) -print

Now it's working.
thanks.
meetvipin
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