Shell Programming and Scripting

How could I using the following example, change it to show 2 days ago within the same time frame 0600 AM to 0600 AM

Code:

let foo=`date "+(1%H-106)*60+1%M-100"` bar=foo+1440
find . -mmin +$foo -mmin -$bar | tr -s '/','-' '^' | cut -f2,3 -d"^" | tr -s '^' ' ' |

Moderator's Comments:

Please use code tags

Code:

perl -e '@T=localtime(time-(2*86400));printf("%02d%02d%02d%02d%02d%02d\n",$T[5]+1900,$T[4]+1,$T[3],$T[2],$T[1],$T[0])'

oooh...

Sorry...mistook your request for a better way of getting today-2's timestamp. I'll keep thinking...

got anything in bash? not familar with perl

okay, so you're effectively looking to 'peg' the search timeframe to a specific window of time, as opposed to the default 24 hour window used by the find command? So, regardless of the time run, it would look only to the file stats managed between 6am and 6am...?

that is correct

Further to your previous posts it is slowly becoming clearer what you are trying to do. I don't think that the "let" line produces the values you expect.

The "find" syntax is definitely wrong.
The "tr" syntax is definitely wrong.
Please provide some sample filenames (or are they directory names?) showing what the filenames (or directory names?) will look like before and after processing.

I think that you mean that the day starts at 06:00:00 and ends at 05:59:59 the following calendar day.
Please give examples of what values you expect in $foo and $bar at say 05:58 and 06:02 on particular calendar days so as to clearly define "today" "yesterday" and "2 days ago".


An obvious idea would be to run the script from cron at 06:00 daily.

Another idea (having just read recent post). If your "find" has -mmin it must have -daystart. The whole process can be done in a single "find" with suitable constants for $foo and $bar regardless of what time it is. The only decision based on the time of day would be which pair of constants to use.

If you have gnu date, it's usable also in bash.

If you can use ksh93, then you can use printf %T.

Example 1,
Example2,
Example 3

Gnu date examples:

Code:

date +%Y-%m-%d --date='28 day ago'
date -d 'today 06:00:00' 
date '+%Y-%d-%m %H:%M' -d 'yesterday 06:00:00'

Gnudate and epoc:

Code:

epoc=$(date -u +%s)

echo $epoc
(( yesterday=epoc-86400 ))

datestr=$(date -d "1970-01-01  $epoc seconds"  )
echo  $datestr
datestr=$(date -d "1970-01-01  $epoc seconds" '+%Y-%m-%d %H:%M:%S' )
echo  $datestr
echo "yesterday:"
date -d "1970-01-01  $yesterday seconds" '+%Y-%m-%d %H:%M:%S'