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awk, grep 'df -lah' into one line

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# 1  
Old 05-12-2010
awk, grep 'df -lah' into one line
Hi Everyone,

Code:
[root@]# df -lah
Filesystem            Size  Used Avail Use% Mounted on
/dev/sda7              75G   59G   13G  83% /
/proc                    0     0     0   -  /proc
sysfs                    0     0     0   -  /sys
devpts                   0     0     0   -  /dev/pts
/dev/sda5              99M   13M   82M  14% /boot
tmpfs                 500M     0  500M   0% /dev/shm
none                     0     0     0   -  /home/neotip/proc
none                     0     0     0   -  /proc/sys/fs/binfmt_misc

[root@]# df -akh | grep "/boot" | awk '{print $5}' | tr -d '\n'
14%

As you can see, i use grep, awk both and tr to remove the '\n', would like to seek one line awk to get the output of "14", without % also.

Thanks
# 2  
Old 05-12-2010
Code:
awk '$NF=="/boot"{sub(/%/,"",$5);print $5}' infile
14

# 3  
Old 05-12-2010
Quote:
Originally Posted by zaxxon
Code:
awk '$NF=="/boot"{sub(/%/,"",$5);print $5}' infile
14

Thanks, finally i use
Code:
df -lah | awk '$NF=="/boot"{sub(/%/,"",$5);print $5}' - | tr -d '\n'

# 4  
Old 05-12-2010
or,

Code:
df -lah | awk '$NF=="/boot"{print int($5)}'

just curious, why do you want to remove the newline?

if you are using this value as a variable, you can do that without that.
Code:
usage=$(df -lah | awk '$NF=="/boot"{print int($5)}')

use nawk or usr/xpg4/bin/awk on solaris
# 5  
Old 05-12-2010
Quote:
Originally Posted by anchal_khare
or,

Code:
df -lah | awk '$NF=="/boot"{print int($5)}'

just curious, why do you want to remove the newline?

if you are using this value as a variable, you can do that without that.
Code:
usage=$(df -lah | awk '$NF=="/boot"{print int($5)}')

use nawk or usr/xpg4/bin/awk on solaris

Thanks, the reason i want to remove % and '\n', bec i want to do the comparsion, like when one partition is over 80 percent, i can do else.
Like my perl file
Code:
next if (`ssh 1.1.1.1 'df -lah' | awk '\$NF=="/boot"{print int(\$5)}' | tr -d '\n'` < 90);

Thanks for your code.
Last edited by jimmy_y; 05-12-2010 at 11:33 AM..
# 6  
Old 05-12-2010
No % and no newline:
Code:
awk '$6=="/boot" {printf($5+0)}'

Regards,
Alister
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