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Cutting out text from specific portion on filename

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Top Forums Shell Programming and Scripting Cutting out text from specific portion on filename
# 15  
Old 05-12-2010
Or, with Perl -

Code:
$
$
$ echo '/dir1/dir2/maybeotherDIRS/http_log.SOMENAME.2010.05.01.00.45.00.230.gz' | perl -pne 's/^.*?\.([\d\.]+)\..*$/$1/'
2010.05.01.00.45.00.230
$
$

tyler_durden
# 16  
Old 05-12-2010
thanks Smilie
Code:
ls -R1 /EMEA/*/*/http_log*.gz |sed  -e 's#.*/##' -e 's#[^0-9][^0-9]*[.]\([0-9][0-9.][0-9.]*\)[.].*#\1#' | cut -d. -f3,4,5 | tr -d "."

Last edited by GermanJulian; 05-12-2010 at 01:33 PM..
# 17  
Old 05-12-2010
I don't think its a good way to invoke three external commands and pipes just to get any sub string. (at least for your requirement).

if your files patterns are same.

Code:
ls -R1 /EMEA/*/*/http_log*.gz | awk -F"." '{print $5$6$7}'
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