Shell Programming and Scripting

Hello,

My input files are having header/body/footer. The first three digits finds whether the data is header/body/footer. For example,

010AAAAA 20100507 234KB BBBBBBBBBB_20100506.DAT
020CCCCC DDDDDDDDD 373983983 19750426 456.90 3983939EE
020FFFFF GGGGGGGGG 38938993H 19801102 783.33 DKJFDKJ983
020JJJJJJ KKKKKKKKKK 8666383L 398.90 DKJFKDLD993
030END OF FILE TOTAL 39839.22

From the above file, there is a date of birth in body (=020). Want to substitute the dateofbirth with # on every 2nd character. Like for ex, 19750426 is the date of birth but want to substiute as "1#7#0#2#". Want to do this same in all records in the file. If there is no value in date-of-birth then leave it as it is (refer 3rd record of 020). Can you please tell me how to do this in shell script?

The content of the file is,
From 1 to 3 = RECORD_TYPE
From 4 to 40 = NAME
From 41 to 80 = DESIGNATION
and so on.

-Nag

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