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chomp like Perl operator in Bash

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# 1  
Old 05-07-2010
chomp like Perl operator in Bash
I am sure there should exist a chomp like Perl operator in Bash using which I can literally remove new line characters as show below:

Quote:
use strict;
use warnings;

my $str1 = "Hello\n";
my $str2 = "World";
print $str1.$str2;

print "\n";

chomp($str1);

print $str1.$str2;

print "\n";
Any clue?
Last edited by paragkalra; 05-07-2010 at 01:48 AM..
# 2  
Old 05-07-2010
Code:
#!/bin/bash
str1="Hello\n"
str2="World"
echo -e "$str1.$str2"
echo -e "\n"

str1="${str1%\\n}"

echo -e "$str1.$str2"
echo -e "\n"

# 3  
Old 05-07-2010
It worked Smilie

I was anticipating some function. Not sure what this line is doing:

Quote:
str1="${str1%\\n}"
# 4  
Old 05-07-2010
${STRING%SUBSTRING} removes SUBSTRING from the end of STRING
\n : the \ must be escaped by \ so thats why i wrote \\n
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