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Shell Programming and Scripting

output problem

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# 1  
Old 05-05-2010
output problem
Code:
#!/bin/gawk -f
BEGIN{}
            
{if ($0~/<a/ || $0~/<img/)
    link=link+1
}
{if ($0~/<a/ || $0~/<img/)
    cnt[$i]++

}
{if ($0~/<a/ && $0~/http/ )
    weblink[$i]++
}
{if ($0~/<img/)
    filelink[$i]++
}
{if ($0~/<a/ && $0!~/http/)
    downloadlink[$i]++
}

END{print "File Name and Path = "FILENAME 
{print "Number of links in file = ",link,"\n"}
for (name in cnt) {print name cnt[name]}
print(" ")
print("The links to other websites, images, and download files: ","\n")
for (name in weblink) {print(name)}
print(" ")
for (name in filelink) {print(name)}
print(" ")
for (name in downloadlink) print(name)
}

ok, guys i have this code, that searches for links in a html file, and, i am using an associative array, for recording the appearance frequency of a link.
but im having difficulties printing the array.
the output is:

3br/> <a href="http://www.facebook.com">Facebook. </a>

as you can see the number is at the begging and not at the end onf the line.

i want the output to be like this:

<br/> <a href="http://www.facebook.com">Facebook. </a> 3
# 2  
Old 05-05-2010
Post an example of the input file and the desired output.
# 3  
Old 05-05-2010
input file:

Code:
<html>
<body>

<h1>Welcome to Page1 Website</h1>
<p1>Hello and welcome to Page1 Website</p1>

<br/> <a href="http://www.youtube.com">Youtube. </a>
<br/> <a href="http://www.facebook.com">Facebook. </a>
<br/> <a href="http://www.facebook.com">Facebook. </a>
<br/> <a href="http://www.facebook.com">Facebook. </a>
<br/> <a href="http://www.youtube.com">Youtube. </a>

<br/> <img src="25061.jpg" width="100" height="100" />
<br/> <img src="25064.jpg" width="200" height="200" />

<br/> <a href="/sample.pdf">pdf document1 </a>
<br/> <a href="/booklet09.pdf">pdf document2 </a>

</body>
</html>

desired output:

Code:
<br/> <a href="http://www.facebook.com">Facebook. </a> 3
<br/> <a href="http://www.youtube.com">Youtube. </a> 2
<br/> <img src="25061.jpg" width="100" height="100" /> 1
<br/> <img src="25064.jpg" width="200" height="200" /> 1
<br/> <a href="/sample.pdf">pdf document1 </a> 1
<br/> <a href="/booklet09.pdf">pdf document2 </a> 1



---------- Post updated at 09:59 AM ---------- Previous update was at 09:54 AM ----------

yeah.. sorry for not using tag codes :S
Last edited by Franklin52; 05-05-2010 at 11:58 AM.. Reason: Please use code tags!
# 4  
Old 05-05-2010
Try and adapt this AWK program :
Code:
#!/bin/gawk -f
{
   if ($0 !~ /<a|<img/) next;
   link++;
   cnt[$0]++;

   if ($0  ~ /<a/) {
      if ($0 ~ /http/)
         weblink[$0]++
      else
         downloadlink[$0]++
   } else
      filelink[$0]++;
}

END {
   print "File Name and Path =",FILENAME;
   print "Number of links in file = ",link,"\n";
   for (name in cnt) print name, cnt[name];
   print("\nThe links to other websites:\n")
   for (name in weblink) print name;
   print("\nThe links to images:\n")
   for (name in filelink) print name;
   print("\nThe links to download files:\n")
   for (name in downloadlink) print name;
}

Output:
Code:
File Name and Path = pantelis.txt
Number of links in file =  9 

<br/> <img src="25061.jpg" width="100" height="100" /> 1
<br/> <img src="25064.jpg" width="200" height="200" /> 1
<br/> <a href="http://www.facebook.com">Facebook. </a> 3
<br/> <a href="/booklet09.pdf">pdf document2 </a> 1
<br/> <a href="http://www.youtube.com">Youtube. </a> 2
<br/> <a href="/sample.pdf">pdf document1 </a> 1

The links to other websites:

<br/> <a href="http://www.facebook.com">Facebook. </a>
<br/> <a href="http://www.youtube.com">Youtube. </a>

The links to images:

<br/> <img src="25061.jpg" width="100" height="100" />
<br/> <img src="25064.jpg" width="200" height="200" />

The links to download files:

<br/> <a href="/booklet09.pdf">pdf document2 </a>
<br/> <a href="/sample.pdf">pdf document1 </a>

Jean-Pierre.
# 5  
Old 05-05-2010
Something like this:

Code:
 
awk '$0 ~ /<a / || $0 ~ /<img / {a[$0]++} END{for(i in a) print i , a[i]}' input_file

# 6  
Old 05-05-2010
Quote:
Originally Posted by aigles
Try and adapt this AWK program :
Code:
#!/bin/gawk -f
{
   if ($0 !~ /<a|<img/) next;
   link++;
   cnt[$0]++;

   if ($0  ~ /<a/) {
      if ($0 ~ /http/)
         weblink[$0]++
      else
         downloadlink[$0]++
   } else
      filelink[$0]++;
}

END {
   print "File Name and Path =",FILENAME;
   print "Number of links in file = ",link,"\n";
   for (name in cnt) print name, cnt[name];
   print("\nThe links to other websites:\n")
   for (name in weblink) print name;
   print("\nThe links to images:\n")
   for (name in filelink) print name;
   print("\nThe links to download files:\n")
   for (name in downloadlink) print name;
}

Output:
Code:
File Name and Path = pantelis.txt
Number of links in file =  9 

<br/> <img src="25061.jpg" width="100" height="100" /> 1
<br/> <img src="25064.jpg" width="200" height="200" /> 1
<br/> <a href="http://www.facebook.com">Facebook. </a> 3
<br/> <a href="/booklet09.pdf">pdf document2 </a> 1
<br/> <a href="http://www.youtube.com">Youtube. </a> 2
<br/> <a href="/sample.pdf">pdf document1 </a> 1

The links to other websites:

<br/> <a href="http://www.facebook.com">Facebook. </a>
<br/> <a href="http://www.youtube.com">Youtube. </a>

The links to images:

<br/> <img src="25061.jpg" width="100" height="100" />
<br/> <img src="25064.jpg" width="200" height="200" />

The links to download files:

<br/> <a href="/booklet09.pdf">pdf document2 </a>
<br/> <a href="/sample.pdf">pdf document1 </a>

Jean-Pierre.

thx, but it seems that i get the first output, that is the

3r/> <a href="http://www.facebook.com">Facebook. </a>

i can't make the number appear at the end of the line.

like this

<br/> <a href="http://www.facebook.com">Facebook. </a> 3

---------- Post updated at 10:18 AM ---------- Previous update was at 10:17 AM ----------
Quote:
Originally Posted by panyam
Something like this:

Code:
 
awk '$0 ~ /<a / || $0 ~ /<img / {a[$0]++} END{for(i in a) print i , a[i]}' input_file

same thing... i get the wrong output... Smilie
# 7  
Old 05-05-2010
wondering , how that can be ..as i teseted and getting the proper output.

Try something like this:

Code:
 
awk '$0 ~ /<a / || $0 ~ /<img / {a[$0]++} END{for(i in a) printf("%s %s\n",i,a[i])}' input_file
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