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Shell Programming and Scripting

String replacement

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# 1  
Old 04-29-2010
String replacement
Hi All,

I have below file which has data in below format.

Code:
#$  | AB_100
| AB_300
()| AB_4
@*(% | AB-789

i want o/p as below format.

Code:
| AB_100
| AB_300
| AB_4
| AB-789

So here there is no standard format.
How we can achieve the same in unix ?

Regards,
Subhash
Last edited by Scott; 04-29-2010 at 06:47 PM.. Reason: Code tags
# 2  
Old 04-29-2010
Code:
sed "s/.*|/|/" file

Code:
awk -F"|" ' { print FS $2 }  ' file

# 3  
Old 04-29-2010
anbu's sed solution will strip all characters before the final pipe in a line. If, instead, you only want to strip characters before the first pipe, use the following.
Code:
sed '/|/s/^[^|]*//'

If the number of pipes is zero or one, they behave identically.

Regards,
Alister
Last edited by alister; 04-29-2010 at 06:45 PM..
# 4  
Old 04-29-2010
This long-awaited (Smilie) perl variant should work as well:
Code:
$ perl -lne '@arrr = split(/\|/); print "|$arrr[1]"' file

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