Shell Programming and Scripting

Hi,

I have many files ex: file1, file2 ...file100, and I would like to rename only files with "1" in name. I don't have experience with bash and other shells. I know I can use "for i in" and "if", and I can use "sed" to change "1" but I have no idea how should "if" look.

I will be grateful for any help or suggestion.

How should the output look like?

something like that

ex:

file1 -> filea
or
file1 -> newfile1

file21 -> file2a
or
file21 -> newfile21

file11 -> fileaa
or
file11 -> newfile11

sh, without if:

Code:

$ for i `ls | grep 1`
do
mv $i new$i
done

in bash:

Code:

[b@b ~/test]$ for i in *
> do
> if [[ $i =~ 1 ]] ; then
> mv $i new$i
> fi
> done

Thanx all of you for helpful information.

And I have another question,

If I would like for ex. copy all files with for ex. read, write and execute permissions, I guess I can use some think like that:

Code:

$ for i `ls -l | grep -rwx...`
do
...
done

But is there any possibility to use in 'for' numbers (ex. 777, 664) ???

Never use this "for" construct:
There is never a reason to use "for" in a construct involving "ls -l" in a commercial environment. If there were 100,000 files the expanded "for" statement would break the shell command line length.
Also the shell command as stated contains multiple syntax errors.


Please rephrase your question in plain English showing examples of "before" and "after" and stating the processing required.

Code:

$ for i in `ls -l | grep '\-rwx' | awk '{ print $NF }'`

There's at least one disadvantage: It will only correctly handle files with no whitespaces in it.
The command above would return 3423.dat if the file's name were "my file 3423.dat"
I don't think you can grep for 777 or the like, but you could adjust your search string to achieve that.