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help pls getting EOF error

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Top Forums Shell Programming and Scripting help pls getting EOF error
# 1  
Old 04-23-2010
help pls getting EOF error
Code:
#!/bin/bash
while :
do
clear
echo ""***************************************"
echo  "*         - MAIN  -  MENU  -          *"
echo  "***************************************"
echo  "* 1.  Directory Listing               *"
echo  "* 2.  Users Currently Logged In       *"
echo  "* 3.  Create a Directory              *"
echo  "* 4.  View a man page                 *"
echo  "* 5.  View a web page                 *"
echo  "* X.  Exit                            *"
echo  "***************************************"
echo ""
echo -n "please enter option [1 - 5] "
read opt
clear
case $opt in
1) echo "++++++ Directory contents ++++++";
        echo"";
        ls -l;
        read enterkey;;
2) echo "++++++ Users currently logged in ++++++";
        echo"";
        read enterkey;;
3) echo "++++++ Create Directory ++++++";
        echo"";
        read enterkey;;
4) echo "++++++ Choose a man page to view ++++++";
        echo"";

5) echo "++++++ choose a web page to view ++++++";
         echo"";
         #read enterkey;;
X) echo "bye $USER";
         exit 1;;
*) echo "$opt is an invalid option, 1 - 5 only";
         read enterkey;;

esac
done

line 46: unexpected EOF while looking for matching `"'
and line 52: syntax error: unexpected end of file
Last edited by Franklin52; 04-23-2010 at 08:51 AM.. Reason: Please use code tags!
# 2  
Old 04-23-2010
This line (5) has an extra quote that knocks everything else out of place:

Code:
echo ""***************************************"

And the last line in case 5 is commented out, removing the ;;

And case 4 only has 1 ;
Last edited by Scott; 04-23-2010 at 09:33 AM..
# 3  
Old 04-23-2010
In addition to the "" issue, there is a ";;" missing in the case statement for option 4.
I've remove all excess trailing semi-colon characters to make it easier to read and put the ;; on a separate line. This is unix shell not Oracle and it is never necessary to end a line in a single semi-colon.

Code:
#!/bin/bash
while :
do
clear
echo "***************************************"
echo "* - MAIN - MENU - *"
echo "***************************************"
echo "* 1. Directory Listing *"
echo "* 2. Users Currently Logged In *"
echo "* 3. Create a Directory *"
echo "* 4. View a man page *"
echo "* 5. View a web page *"
echo "* X. Exit *" echo "***************************************"
echo "" echo -n "please enter option [1 - 5] "
read opt
clear
     case $opt in
     1) echo "++++++ Directory contents ++++++"
        echo""
        ls -l
        read enterkey
        ;;
     2) echo "++++++ Users currently logged in ++++++"
        echo""
        read enterkey
        ;;
     3) echo "++++++ Create Directory ++++++"
        echo""
        read enterkey
        ;;
     4) echo "++++++ Choose a man page to view ++++++"
        echo""
        ;;
     5) echo "++++++ choose a web page to view ++++++"
        echo""
        #read enterkey
        ;;
     X) echo "bye $USER"
        exit 1
        ;;
     *) echo "$opt is an invalid option, 1 - 5 only"
        read enterkey
        ;;
esac
done

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