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Sorting inside awk

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# 1  
Old 04-22-2010
Sorting inside awk
I have an array with five columns and i want to write it to a file.
Before writing it i must sort it using the field in the fifth column.

Code:
_________________________________________
|field 1|field 2|field 3|field 4|field 5|
|       |       |       |       |       |
|       |       |       |       |       | 
|       |       |       |       |       |
|       |       |       |       |       |
|       |       |       |       |       |
|_______|_______|_______|_______|_______|

Note that gawk is not available so either i have to write my own sort function or i have to use another way.
Any suggestions?
# 2  
Old 04-22-2010
My advice is to use the unix sort which is by far simpler.
To do a awk sort, you would need to write a sort function which is not elegant
# 3  
Old 04-22-2010
Quote:
Originally Posted by ForestRun
My advice is to use the unix sort which is by far simpler.
To do a awk sort, you would need to write a sort function which is not elegant
Yeah ok but can i call it inside an awk file, and if yes how.
# 4  
Old 04-22-2010
something likes this?

Code:
awk '{print|"sort -k4" }' urfile

# 5  
Old 04-22-2010
Quote:
Originally Posted by rdcwayx
something likes this?

Code:
awk '{print|"sort -k4" }' urfile

Ok but i haven't got a file as an input. I have a table.
# 6  
Old 04-23-2010
Refer to this:
Awk sort
# 7  
Old 04-23-2010
Quote:
Originally Posted by ForestRun
Refer to this:
Awk sort
Thanks but didn't make any difference.
My question remains.
I have a multidimensional array inside an awk program. This array has five columns and i want to sort it using the field in the fifth column (btw the field there is arithmetic). Is there a way to do it?
Note that gawk is not an option!
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