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printing array elements inside AWK

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# 1  
Old 04-20-2010
printing array elements inside AWK
i just want to dump my array and see if it contains the values i am expecting. It should print as follows,
ignore[0]=345fht
ignore[1]=rthfg56
.
.
.
ignore[n]=49568g

Here is the code. Is this even possible to do? please help



Code:
 
termReport.pl < $4 | dos2ux |  head -2000 | awk '
    BEGIN { foundTermEvent=0;
            endMarker="'"${endMarker}"'"; }
    {
      if ( (substr($0, 1, length(endMarker)) == endMarker) ||
           (substr($0, 1, 39) == "'${SBINDIR}'/termReport.pl: ") )
      {
        if (foundTermEvent == 1)
        {
          print "";
          foundTermEvent=0;
        }
      }
      if (foundTermEvent == 1)
      {
            z=0
            while ( z <= leanth_of_ignore )
            {
                if ( ignore[z] == $2 )
               {
               foundTermEvent = 0;
               { print ignore[z] }
               z=31
               }
               else
               {
               print;
               { print ignore[z] }
               z++
               }
            }
      }
      if (substr($0, 1, 18) == "Termination Event:")
      {
        foundTermEvent=1;
      }
    }'

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NAME

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SYNOPSIS

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DESCRIPTION

       ckport is a tool to check already compiled binaries and libraries for porting and security problems.

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       --noheader
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       --file-header
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       --ignore PATTERN
	      Ignore symbols matching this Perl regex pattern.

       --ignore-symbol SYMBOL
	      Ignore symbol SYMBOL.

       --ignore-target TARGET
	      Ignore warnings for target TARGET.

       --print-mode MODE
	      Set mode of symbol printing to MODE.

       --print-unknown
	      Print unknown symbols found.

       --print-unknown-defined
	      Print list of unknown but defined (internal) symbols.

       --print-unused
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       --print-pt
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SEE ALSO

       objdump(1).

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