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Sed - Printing

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# 1  
Old 04-14-2010
Sed - Printing
Hi,

I need to print the lines between 2 pattern.

Eg

aaa
1
2
3
4
5
bbb

Required Output

aaa
1
2
3
4
5

I tried sed -n '/aaa/,/bbb/p' , but it prints the bbb also.

Thank you,
Sreedevi
# 2  
Old 04-14-2010
While thinking of something better..

Code:
$ sed -n "/bbb/q; /aaa/,/bbb/p" file1

aaa
1
2
3
4
5

# 3  
Old 04-14-2010
Thanks Scott!
It works perfectly fine.

Let me make my question generic
a4_*
a
s
f
a4_aa
1
2
3
4
5
a4_*
6
7
8
a4_*
9
10
a4_cc
11
12


(1)I need to print between a4_aa and the next a4_*
(2) what happens if my a4_aa is the last one and after that it does not see the a4_* paatern

Thanks,
Sreedevi
# 4  
Old 04-14-2010
MySQL
1-)
Code:
[root@sistem1lnx ~]# cat 12
a4_aa
1
2
3
4
5
a4_*
6
7
8
a4_*
[root@sistem1lnx ~]# sed -n '/a4_aa/,/a4_*/p' 12
a4_aa
1
2
3
4
5
a4_*

2-)if the a4_aa last line the output is only contains "a4_aa" line Smilie
Code:
[root@sistem1lnx ~]# cat 12
a4_*
6
7
8
a4_*
a4_aa  
[root@sistem1lnx ~]# sed -n '/a4_aa/,/a4_*/p' 12
a4_aa

#Last Line and doesnt exist "a4_*" in next lines

or
Code:
[root@sistem1lnx ~]# sed -n '/a4_aa/,/a4_*/{;/a4\_\*/!p;}' 12
a4_aa
1
2
3
4
5

Regards
Last edited by ygemici; 04-14-2010 at 06:57 AM..
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