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Shell Programming and Scripting

move datestamp to beginning of line where available

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# 1  
Old 04-09-2010
move datestamp to beginning of line where available
My current output is as follows:
Code:
All Day Event
Someone's Birthday
Class 7:00 PM
Pick up dry cleaning 1:00 PM
Wake up 8:00 AM

I'd like the output to remain the same but have the times moved to the beginning of the line with a hyphen after it so it would look like,

Code:
All Day Event
Someone's Birthday
7:00 PM - Class 
1:00 PM - Pick up dry cleaning
8:00 AM - Wake up

I assume that this can be done with awk and regex? I'm just not sure how.

I tried searching but have no idea what I'm trying to do would even be called.

The closest I got was
Code:
awk '{if ( $NF == "PM" || $NF == "AM" ) { print $(NF-1),$NF,"-",$0 } else {print $0}}'

Last edited by chrish; 04-09-2010 at 04:53 PM..
# 2  
Old 04-09-2010
Code:
nawk '$(NF-1) ~ "\:[0-9][0-9]" {print $(NF-1),$NF,"-",$0}' infile

# 3  
Old 04-09-2010
Code:
sed 's/\(.*\) \([0-9][0-9:]* [PA]M\)/\2 - \1/'  myFile

# 4  
Old 04-09-2010
Quote:
Originally Posted by EAGL€
Code:
nawk '$(NF-1) ~ "\:[0-9][0-9]" {print $(NF-1),$NF,"-",$0}' infile

my output is showing up as
Code:
All Day Event - All Day Event
Someone's Birthday - Someone's Birthday
7:00 PM - Class 7:00 PM
1:00 PM - Pick up dry cleaning 1:00 PM
8:00 AM - Wake up 8:00 AM





Quote:
Originally Posted by vgersh99
Code:
sed 's/\(.*\) \([0-9][0-9:]* [PA]M\)/\2 - \1/'  myFile

That did it. Thanks!
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