Ignoring newlines in my search


 
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Top Forums Shell Programming and Scripting Ignoring newlines in my search
# 8  
Old 04-08-2010
Here it goes:

Code:
 
'/low/ && $0 ~ /0 $/ {print ; next } --> lines have "low" and "0 " , so just print them and go to next line
  
/low/ { a=$0;next } --> if the line have "low" , store it in "a" , go to next line
 
$0 ~ /0 $/ {a=a""$0;print a ;a=""} --->  if the line have "0 " in the end , print a , and reset a to nothing.
 
{a=a""$0;next}' input_file --> append the line to "a" , and go to next line ( search till you get a line with "0 " in the end).

To be more accurate use below:
Code:
 
 
awk '/^low/ && $0 ~ /0 $/ {print ; next } /^low/ { a=$0;next } $0 ~ /0 $/ {a=a""$0;print a ;a=""} {a=a""$0;next}' input_file

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UNIQ(1) 						      General Commands Manual							   UNIQ(1)

NAME
uniq - report repeated lines in a file SYNOPSIS
uniq [ -udc [ +n ] [ -n ] ] [ input [ output ] ] DESCRIPTION
Uniq reads the input file comparing adjacent lines. In the normal case, the second and succeeding copies of repeated lines are removed; the remainder is written on the output file. Note that repeated lines must be adjacent in order to be found; see sort(1). If the -u flag is used, just the lines that are not repeated in the original file are output. The -d option specifies that one copy of just the repeated lines is to be written. The normal mode output is the union of the -u and -d mode outputs. The -c option supersedes -u and -d and generates an output report in default style but with each line preceded by a count of the number of times it occurred. The n arguments specify skipping an initial portion of each line in the comparison: -n The first n fields together with any blanks before each are ignored. A field is defined as a string of non-space, non-tab charac- ters separated by tabs and spaces from its neighbors. +n The first n characters are ignored. Fields are skipped before characters. SEE ALSO
sort(1), comm(1) UNIQ(1)