Shell Programming and Scripting

Here is my code, in sh

Code:

#!/bin/sh

x=${1##*.}
#for i in $*; do
#Modified per alister's tip
for i; do
    [ $x != ${i##*.} ] && {
        echo "All extensions are NOT alike."
        exit 1
    }
done
echo "All extensions ARE alike."

exit 0

That will break if there are any filenames with IFS characters (space/tab/newline by default). Instead, use one of the following:

Code:

for i; do

or

Code:

for i in "$@"; do

Regards,
Alister

Thanks for the tip

A warning about shift, I think Alister first mentioned it:

If you shift through all of your positional parameters, they are all gone.
From bash documentation:
You can use bracket notation to step thru the positional parameters without destroying them. one way:

Code:

while [[ $i -le $# ]]
do
 echo \$${i}
 i=$(( $i + 1 ))
done

Good point, jim. I've edited my solution a few times. First iteration shifted once. Then it did not shift. Then the shift creeped back in. Now it's back out. I wasn't considering that this could be part of a larger script and viewed the shift as inconsequential.

Alister

---------- Post updated at 02:58 PM ---------- Previous update was at 02:39 PM ----------

Unless that's a newer shell feature with which I am not familiar, I think what you're attempting requires some eval magic. Perhaps something like:

Code:

while [[ $((++i)) -le $# ]]
do
    eval echo \${$i}
done