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How to get input xml file as XMLout. output.

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Old 04-06-2010
How to get input xml file as XMLout. output.
Hi ,
I am trying to get an reference of a XML formatted data using XML::Simple::XMLin

and again trying to retrive the XML data as it was before using XML::Simple::XMLout.

But finding a deviation in the format can any pls help me out.

Input file sr.xml
Code:
<?xml version="1.0" encoding="ISO-8859-1" ?>
<scenario>
<counter>
  <counterdef name="HbH-counter" init="1000"> </counterdef>
  <counterdef name="EtE-counter" init="2000"> </counterdef>
  <counterdef name="session-counter" init="10005"> </counterdef>
</counter>
</scenario>

perl code
Code:
 my $data='';
 $file_to_parse='sr.xml';
 my $xml = new XML::Simple;
 my $config = eval { XML::Simple::XMLin("$file_to_parse") };
 $data = $xml->XML::Simple::XMLin("$file_to_parse",keeproot => 1);
 print $xml->XMLout($data,outputfile =>'/var/tmp/Call',keeproot => 1);

outputfile('/var/tmp/Call')
Code:
<scenario>
  <counter name="counterdef">
    <EtE-counter init="2000" />
    <HbH-counter init="1000" />
    <session-counter init="10005" />
  </counter>
</scenario>

My expectation was as it was before :
Code:
<?xml version="1.0" encoding="ISO-8859-1" ?>
<scenario>
<counter>
  <counterdef name="HbH-counter" init="1000"> </counterdef>
  <counterdef name="EtE-counter" init="2000"> </counterdef>
  <counterdef name="session-counter" init="10005"> </counterdef>
</counter>
</scenario>

Last edited by Yogesh Sawant; 04-06-2010 at 04:18 AM.. Reason: added code tags
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