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Howto: easy date range iteration/counting on GNU systems in the shell

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Old 04-05-2010
Howto: easy date range iteration/counting on GNU systems in the shell
Should work in any shell, but requires GNU date, although GNU date seems only to be happy for input dates between 1902 and 2037, inclusive (49673 days).

Assume $a and $b hold two dates, e.g.
Code:
set a=2010-03-27
set b=2010-04-04

Marginally faster:
Code:
iterator: seq -f "$a +%1.0f days" 1 50000 | date +%F -f - 2>&1 | grep -F -B50000 -m1 `date +%F -d"$b"`
count: seq -f "$a +%1.0f days" 1 50000 | date +%F -f - 2>&1 | grep -F -B50000 -m1 `date +%F -d"$b"` | wc -l

More elegant:
Code:
iterator: yes | sed -n = | sed -e "s/.*/$a +& days/" | date +%F -f- 2>&1 | sed /`date +%F -d"$b"`/q
count: yes | sed -n = | sed -e "s/.*/$a +& days/" | date +%F -f- 2>&1 | sed -n /`date +%F -d"$b"`'/{=;q}'


For newbies, to use the iterator, simply do something like:
Code:
yes | sed -n = | sed -e "s/.*/$a +& days/" | date +%F -f- 2>&1 | sed /`date +%F -d"$b"`/q | while read date; do
   echo "$date is in the range" # or whatever
done

Hope someone finds this useful.
Last edited by laddiebuck; 04-05-2010 at 04:22 PM.. Reason: Just noticed the last one didn't work in csh. Also made it grep -F, why not? Also some stress testing.
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