Shell Programming and Scripting

hey guys!

I need to find in a specific directory and its sub-directories a file thats passed has a argument, and print it has like a ls -l command! the problem is how do i print has a ls command but instead only the file name in the end, also the directory where its insered!


ex:

Want to find in a specific dir a file named hello.txt, but this dir is inside another one thats the "mainDir"!
and the output has to be like a ls-l output but instead of only:

drwxr-xr-x 3 kk kk 4096 date time hello.txt
drwxr-xr-x 3 kk kk 4096 date time insiredDir/hello.txt


So my idea was to do a: find ~/mainDir -name 'roflmao.txt' > help.txt
putting all existing files paths inside this txt
Then do a while to grab all paths 1 by 1 and and do a ls -l (since it has to be outputted that way). So far so good! but the outputted ls has i said only has to give the file that i looked for and its insired dir like in ex above!

Any suggestion of doing another way or ...? :x

Thanks in advanced!

Did you meant like this?

Code:

 
find -type f -name '*test*' -exec ls -lh {} \;

Code:

-rw-r--r-- 1 root root 0 Mar 26 08:42 ./feed/3teste33
-rw-r--r-- 1 root root 0 Mar 26 08:42 ./feed/33teste33
-rw-r--r-- 1 root root 0 Mar 26 08:42 ./11teste11
-rw-r--r-- 1 root root 0 Mar 26 09:22 ./this/11teste11
-rw-r--r-- 1 root root 0 Mar 26 09:22 ./this/22teste22
-rw-r--r-- 1 root root 0 Mar 26 09:22 ./this/test1
-rw-r--r-- 1 root root 0 Mar 26 09:22 ./this/3teste33
-rw-r--r-- 1 root root 0 Mar 26 09:22 ./this/33teste33
-rw-r--r-- 1 root root 0 Mar 26 09:22 ./this/test2
-rw-r--r-- 1 root root 0 Mar 26 08:42 ./bound/22teste22
-rw-r--r-- 1 root root 0 Mar 26 08:30 ./filezip/test1
-rw-r--r-- 1 root root 0 Mar 26 08:30 ./filezip/test2

yeah that worked! cheers!

i was trying with

find -maxdepth 2 -type f -name "*teste*" | xargs ls -l

but that works better since of depth is only good for some speccific depth files =)