Shell Programming and Scripting

I have a data file that has 6 columns and I have sorted the 3rd column so that all rows are sorted according to the 3rd column (from lowest to highest number). An example is shown below:

7563 273 1 -15.81100000 25.37250000 -19.27320000
8149 294 1 -17.90540000 -6.59144000 -26.03650000
8242 297 2 -13.49870000 19.54790000 -13.56060000
10003 362 3 -13.49950000 23.41270000 -21.26740000
10049 363 4 -12.82110000 14.94900000 -20.00750000
10080 364 5 -12.91600000 2.18556000 -26.58310000
10096 365 5 -15.61200000 4.07117000 -22.90540000
10142 366 6 -13.30700000 10.08880000 -23.34130000
10173 367 6 -18.49690000 13.56170000 31.67000000

I am trying to write a code in awk that will scan through the rows and give me output like how many times each number is appearing in the 3rd column i.e. the frequency with which numbers are appearing. The first column can be the number and the 2nd column is the number of times its appearing. I want the output like this (in reference to data above). I am new to awk so I need some guidance.

1 2
2 1
3 1
4 1
5 2
6 2

Code:

awk '{a[$3]++} END {for (i in a) print i, a[i]|"sort -n"}' urfile

thanks rdcwayx,
the code worked perfectly...........thanks a lot.

Since the file is sorted you can also do something like:

Code:

awk 'c && s!=$3{print s,c;c=0} {s=$3;c++} END {print s,c}' file