Shell Programming and Scripting

I'm trying to use sed to insert data at a specific column, let's say my data looks like this:

0553 1828
0552 1829
0550 1829
0549 1830
0548 1831

what I want is this:

timein 0553 timeout 1828
timein 0552 timeout 1829
timein 0550 timeout 1829
timein 0549 timeout 1830
timein 0548 timeout 1831

So inserting at a beginning of a line is easy, that would be:

cat inputfile | sed 's/^/timein /g' > outputfile

it's inserting the "timeout" that throwing me. Any help would be appreciated.

Code:

awk '{print "timein",$1,"timeout", $2}' urfile

Sticking w sed AND the assumption of two columns separated by space(s):

Code:

sed -e "s/ +/timeout/g" -e "s/^/timein/g" filename

---------- Post updated at 00:38 ---------- Previous update was at 00:38 ----------

Sticking w sed AND the assumption of two columns separated by space(s):

Code:

sed -e "s/ +/timeout/g" -e "s/^/timein/g" filename

Thanks guys!

We can combine as

Code:

 
sed 's/\([0-9]*\) \([0-9]*\)/Timein \1 Timeout \2/g' < file

Code:

sed 's/^\(.[^ \t]*\)[ \t]*\(.[^ \t]*\)/timein \1 timeout \2/' file