How to see the list of files which exists with nonzero bytes


 
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# 1  
Old 03-20-2010
How to see the list of files which exists with nonzero bytes

Hi,

I would like to see the file list which contains the data.

Ex : - When I enter the "ls -ltr" command it will show all the files which are exists in the directory, But I want only those files list which are non zero byte by using only ls command.

I knew that I can write a script with "-s" option through script but I want the list through ls command...

For better understanding I am posting with example : -

$ls -ltr
-rw-r--r-- 1 userID MyGroup 0 Mar 2 10:27 a.txt
-rw-r--r-- 1 userID MyGroup 0 Mar 2 10:27 b.txt
-rw-r--r-- 1 userID MyGroup 50 Mar 2 10:27 c.txt
-rw-r--r-- 1 userID MyGroup 0 Mar 2 10:27 d.txt
-rw-r--r-- 1 userID MyGroup 200 Mar 2 11:24 e.txt
-rw-r--r-- 1 userID MyGroup 0 Mar 4 03:14 f.txt
-rw-r--r-- 1 userID MyGroup 100 Mar 4 03:14 g.txt
-rw-r--r-- 1 userID MyGroup 0 Mar 4 03:14 h.txt
-rw-r--r-- 1 userID MyGroup 0 Mar 4 03:14 i.txt

I want to see only c.txt, e.txt and g.txt from the above list, not all.

Please advice me how to solve this.

---------- Post updated at 05:17 AM ---------- Previous update was at 05:15 AM ----------

I don't want to delete the 0 byte files, I want to list out only those files which caontains data.
kandi.reddy
# 2  
Old 03-20-2010
Try this,

Code:
ls -lrt | sed -r "s/(.+\s+.+\s+.+\s+.+\s+0\s+.+)//g"

# 3  
Old 03-20-2010
When I try the below command.....I am getting the "illegal option" meesage.

Code:
$  ls -lrt | sed -r "s/(.+\s+.+\s+.+\s+.+\s+0\s+.+)//g"
sed: illegal option -- r
$


Last edited by radoulov; 03-20-2010 at 09:01 AM.. Reason: Please use code tags!
kandi.reddy
# 4  
Old 03-20-2010
I am working in linux system which has the version 2.6.26-2-686.The '-r' option in sed is available in this .
# 5  
Old 03-20-2010
MySQL

See the following command.
Code:
ls -lrt | egrep -v "(.*) (.*) (.*) 0 (.*) (.*) (.*)"


or

Code:
ls -lrt | egrep -v "(.*?) (.*?) (.*?) 0 (.*?) (.*?) (.*?)"

# 6  
Old 03-20-2010
Thank you, I am getting the results what I am looking for.

But Could you please explain me how it works....It would be very great....
kandi.reddy
# 7  
Old 03-20-2010
MySQL

Quote:
Originally Posted by kandi.reddy
Thank you, I am getting the results what I am looking for.

But Could you please explain me how it works....It would be very great....

egrep is equal to grep -E

Using regular expression I matched the pattern.
-v option is used to invert match options.

( ) = grouping in regular expression.

For More information refer the following link.
Regular Expressions in grep
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