how to get what date was 28 days ago of the current system date IN UNIX


 
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# 15  
Old 03-18-2010
Date calculation, yesterday, today, date format, epoc, ...

There has been lot of date calculation solution in this forum.

If you have Gnu date, then you can use previous date command.

If you have ksh93, then you can use ksh printf builtin
calculation including your format needs.

Read
Read more
And more

Some date calculation examples using ksh93 + printf:

Code:
#!/bin/ksh93
#date
printf "%T\n" now
printf "%(Today is %F or you can write %d.%m.%Y ...)T  \n" now

# save date to variable in standard format
timestamp=$(printf "%(%F+%H:%M:%S)T" now)
echo "timestamp:$timestamp"

# convert timestring as integer using variable
timestamp=$(printf "%(%Y-%m-%d+%H:%M:%S)T" now)
timeint=$(printf "%(%#)T" "$timestamp")
echo "timestamp:$timestamp"
echo "timeint:$timeint"
((daysec=24*60*60))
((yesterday=timeint - daysec))
((tomorrow=timeint + daysec))
# argument is # + date integer
#same = give integer using #char
printf "yesterday %(%Y-%m-%d)T  \n" "#$yesterday"
printf "tomorrow %(%Y-%m-%d)T  \n" "#$tomorrow"

sec19700101=$(printf "%(%s)T" "$d")
echo "sec since 1970-01-01 00:00 UTC: $sec19700101"
echo "= same as timeint:$timeint"

printf "day of week, monday=1: %(%u)T  \n" '#'$timeint
printf "weeknr, monday is first day of week: %(%V)T  \n" '#'$timeint

oldday=$(printf "%(%#)T"   "2008-08-15+00:00:00")
today=$(printf "%(%#)T"   "2009-08-15+00:00:00")
(( diff=(today-oldday)/(24*60*60)  ))
echo "diff:$diff"

((daysec=24*60*60))
dstr=20100228
y=${dstr:0:4}
m=${dstr:4:2}
d=${dstr:6:2}

day=$(printf "%(%#)T"   "$y-$m-$d+00:00:00")
((prev=day-daysec))
printf "%(%Y%m%d)T  \n" "#$prev"
day=$(printf "%(%#)T"   "$y-$m-$d")
((next=day+daysec))
printf "%(%Y%m%d)T  \n" "#$next"

You can download ksh93 for SunOS if you not have it.

Last edited by kshji; 03-18-2010 at 12:52 PM..
# 16  
Old 03-19-2010
Thank you one and all for your valuable solutions and guidence.
kandi.reddy
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